WebIf 10 4dm3 of water is introduced into 1.o dm3 flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established? (Given: Vapour pressure of … Web25 sep. 2024 · Solution: We will first calculate the value of pressure. We know from the ideal gas equation PV = nRT P = 1 x 8.33 x 300 / 5 P = 500 atm Now we know this is an isobaric process with pressure constant. Therefore the work done will be equal to W = PdV W = 500 (V2 - V1) W = 500 ( 10 - 5) W = 2500 J
If 10^-4 dm^3 of water is introduced into a 1.0 dm^3 flask at 300 …
WebIf 10 −4dm 3 of water is introduced into 1.0 dm 3 flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established? [Given: Vapour pressure of H … Web11 okt. 2024 · If 10-4 dm3 of water is introduced into a 1.0 dm3 flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established (Given : Vapur pressure of H2O at 300 K is 3170 Pa; R = 8.314 J K-1 mol-1) (a) 1.27 x 10-3 mol (b) 5.56 x 10-3 mol (c) 1.53 x 10-3 mol (d) 4.46 x 10-3 mol gases and liquids class-11 1 Answer +1 … cabinet kine kunheim
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Web15 mei 2024 · For the reaction of H2 with I2, the rate constant is 2.5 × 10–4 dm3 mol–1 s –1 at 327°C and 1.0 dm3 mol–1 at 527°C. The activation energy for the reaction, in kJ mole–1 is : (R = 8.314 JK–1 mol–1 ) (1) 59 (2) 166 (3) 72 (4) 150 jee mains 2024 1 Answer +1 vote answered May 15, 2024 by Bhawna (68.7k points) selected May 15, 2024 by faiz Best … Web29 aug. 2024 · If 10^-4 dm3 of water is introduced into a 1.0 dm^3 flask to 300k, how many moles of water are in the vapour phase when equilibrium is established? The q value of a nuclear reaction is defined by The potential energy of an electron in a hydrogen atom is 6.8 The potential energy of an electron in the second excited state in hydrogen atom WebIf 10 −4dm 3 of water is introduced into 1.0 dm 3 flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established? [Given: Vapour pressure of H 2O at 300 K is 3170 Pa; R=8.314JK −1mo1 −1] A 5.56 ×10 −3 mol B 1.53 ×10 −2 mol C 4.46 ×10 −2 mol D 1.27 ×10 −3 mol Medium Solution Verified by Toppr Correct option is D) cabman rittenstaat online nl